已知线性方程组 X1+X2+2X3-3X4=1 X1+2X2-X3+2X4=3 2X1+3X2+X3-X4=B B取何值,方程组无解 B取何值,方程组有解,并求通解,

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已知线性方程组 X1+X2+2X3-3X4=1 X1+2X2-X3+2X4=3 2X1+3X2+X3-X4=B B取何值,方程组无解 B取何值,方程组有解,并求通解,
已知线性方程组 X1+X2+2X3-3X4=1 X1+2X2-X3+2X4=3 2X1+3X2+X3-X4=B
B取何值,方程组无解
B取何值,方程组有解,并求通解,

已知线性方程组 X1+X2+2X3-3X4=1 X1+2X2-X3+2X4=3 2X1+3X2+X3-X4=B B取何值,方程组无解 B取何值,方程组有解,并求通解,
首先是系数矩阵的秩
1 1 2 -3
1 2 -1 2
2 3 1 -1
矩阵初等变换得到
1 1 2 -3
0 1 -3 5
0 0 0 0
秩为2
增广矩阵
1 1 2 -3 1
1 2 -1 2 3
2 3 1 -1 B
初等变换
1 1 2 -3 1
0 1 -3 5 2
0 0 0 0 B-2
使方程组无解 增广矩阵秩和系数矩阵秩不同 当B=2时秩相同 B不=2时秩不同
通解=特解+基础解系
当B=2时 方程组解 {2,0,1,1}+k1{-5,3,1,0}+k2{8,-5,0,1} k1,k2为任意常数 x3和x4为自变量

Cartier
Each and every bit of jewelry is really a legend
Founded in 1847, a century jewelry brands Cartier, bearing the royal family has its distinctive artistic style and luxury Juan says the...

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Cartier
Each and every bit of jewelry is really a legend
Founded in 1847, a century jewelry brands Cartier, bearing the royal family has its distinctive artistic style and luxury Juan says the legendary era wholesale from China .
Founded in 1847, a century jewelry brands Cartier, bearing the royal family members has its exclusive artistic style and luxurious era from the legendary Juan says, produced the design and style of a lot of females by way of the years, did with Cartier-known females ever is closely linked The Duchess of Windsor, Princess of Monaco Grace Kelly, the Mexican actress Maria Felix, and Hollywood star Elizabeth Taylor, probably the most representative and the interpretation of Cartier jewelry inside the "legend, the noble, mysterious power " from the four main style characteristics. Due to the fact individual animals Cartier series of design particularly like, so these four Mexican actress Maria Felix inside the story of the crocodile necklace was particularly impressed, said that when she raised the drop ship wholesalers piece of their very own to obtain the small crocodile Cartier store, said: "to cause me to feel a necklace specifically the identical! " sharp and tough style!
Probably the most notable recent Cartier makes a brand new event very first, the legendary British prince wedding ceremony, the new crown princess Kate is wearing diamond jewelry from the jeweler Cartier Emperor, called "Halo", produced in 1936 , purchased by the Duke of York to give his wife along with a daughter Elizabeth, 18 years old birthday gift. Conventional Wedding in the body to a bride to be "a little bit new wholesale jeans , a little older, a little borrowed, a little blue. " is said, to follow along with Kate's wedding customs within the UK "Something Borrowed" the practice, put on This 1 borrowed from the noble Queen in the diamond crown, together with continued and Cartier began to write a brand new legend.

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求解线性方程组 X1+X2+X3=6 2X1+3X2+X3=11 X1-X2+2X3=5 应用克拉默法则解线性方程组:2X1-X2+3X3=53X1+X2-5X3=54X-X2+X3=9 已知线性方程组:x1+x2+x3=3,2x1+3x2+x3=1,3x1+4x2+2x3=4已知线性方程组:x1+x2+x3=3,2x1+3x2+x3=1,3x1+4x2+2x3=4求方程所有解第二题如图. 解线性方程组 x1-x2-x3=2 x1+x2+4x3=0 3x1+5x3=3 解线性方程组 X1-2X2+3X3-4X4=0 X2-X3+X4=0 X1+3X2-3X4=0 X解线性方程组X1-2X2+3X3-4X4=0X2-X3+X4=0X1+3X2-3X4=0X1-4X2+3X3-2X4=0 线性方程组{2x1-x2-2x3=λx1{5x1-3x2-3x3=λx2{-x1+2x3=-λx3有非零解,则λ= 求解非齐次线性方程组x1+x2+x3=3,x2-x3=0,-x1-x2+2x3=0,2x1-x2+x3=2 用基础解系表示线性方程组的全部解(1)【2x1-x2+x3-2x4=1 】(2) 【x1-2x2+x3=-5】 (3) 【x1-x2-x3+x4=0】【-x1+x2+2x3+x4=0 】 【x1+5x2-7x3=2】 【x1-x2+x3-3x4=1】【x1-x2-2x3+2x4=-0.5 】 【3x1+x2-5x3=-8】 【x1-x2-2x 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X+X3-X4=1 2X1+3X2+X3+X4=12X1+2X2+2X3-X4=15X1+5X2+2X3=22.3 1 0A= -4 -1 0 的特征值和特征向量.4 -8 2 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X2+X3-X 求线性方程组X1-X2-X3+X4=O X1-X2+X3-3X4=0 X1-X2-2X3+3X4=0 的通解并用础解系表示求救 X为字母X 已知齐次线性方程组:①x1-2x2-6x3=0 ②x1+入x2-3x3=0 ③2x1+x2+3x3=0 有无穷多解,则必有入=_______? 解线性方程组:﹛2x1-x2+3x3=0 x1-3x2+4x3=0 -x1+2x2+3x3=0 x后面的数字全为下角马 线性方程组求解,x1+2x2+x3-x4=1 3x1+6x2-x3-3x4=0 线性代数!解非其次线性方程组;【2x1+x2-x3+x4=1;4x1+2x2-2x3+x4=2;2x1+x-x3-x4=1】. 解下列线性方程组 x1+2x2+3x3=1 2x1+2x2+5x3=2 3x1+5x2+x3=3 解线性方程组X1+X2+X3=6,2X1+3X2+3X3=15,2X1+2X2+3X3=13求详解 求解下列非齐次线性方程组!x1-2x2+3x3-x4=13x1-x2+5x3-3x4=22x1+x2+2x3-2x4=3 解线性方程组x1+x2+x3+x4=2;2x1+3x2+4x3+3x4=5;x1+3x2+5x3+3x4=4