用因式分解法解方程：(3y-1)²-8(3y-1)+15=0 4(y+1)²-9（y-1）²=0急······

用因式分解法解方程：(3y-1)²-8(3y-1)+15=0 4(y+1)²-9（y-1）²=0急······
用因式分解法解方程：(3y-1)²-8(3y-1)+15=0 4(y+1)²-9（y-1）²=0
急······

用因式分解法解方程：(3y-1)²-8(3y-1)+15=0 4(y+1)²-9（y-1）²=0急······
①
(3y-1)²-8(3y-1)+15=0
(3y-1)²-8(3y-1)+16-1=0
(3y-1)²-8(3y-1)+4²=1
[(3y-1)-4]²=1
(3y-5)²=1
则有：
3y-5=1
3y-5=-1
解得：
y1=2
y2=4/3
②
4(y+1)²-9(y-1)²=0
[2(y+1)]²-[3(y-1)]²=0
[2(y+1)+3(y-1)][2(y+1)-3(y-1)]=0
(5y-1)(-y+5)=0
则有：
5y-1=0
-y+5=0
解得：
y1=1/5
y2=5

(3y-1-3)(3y-1-5)=0;(3y-4)(3y-6)=0;y=2或y=4/3;
[2y+2-3(y-1)][2y+2+3(y-1)]=0;(5y-1)(-y+5)=0;y=5或y=1/5;

(3y-1)²-8(3y-1)+15=0
（3y-1-3）（3y-1-5）=0
(3y-4)(3y-6)=0
y1=4/3
y2=2

4(y+1)²-9（y-1）²=0
(2y+2+3y-3)(2y+2-3y+3)=0
(5y-1)(-y+5)=0
y1=1/5 y2=5