Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是思路!Thank you!1(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是

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Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是思路!Thank you!1(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是
Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是
思路!Thank you!1
(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是

Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是思路!Thank you!1(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是
(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2恒成立的A,B,C的值依次是
（A+1）x²-（2+B）xy-y²=5x^2-9+Cy^2;
∴A+`1=5;
2+B=9;
C=-1;
∴A=4;B=7;C=-1;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,

(Ax^2-2xy+y^2)-(-x^2+Bxy+2y^2)=5x^2-9+Cy^2
Ax^2-2xy+y^2+x^2-Bxy-2y^2=5x^2-9+Cy^2
(A+1)x^2-(2+B)xy-y^2=5x^2-9+Cy^2
所以A+1=5
2+B=9
-1=c
所以
A=4
B=7
C=-1

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