当x=根号2+1时,求x+1减去x²/x-1

当x=根号2+1时,求x+1减去x²/x-1
当x=根号2+1时,求x+1减去x²/x-1

当x=根号2+1时,求x+1减去x²/x-1
原式=(x²-1-x²)/(x-1)
=-1/(x-1)
=-1/(√2+1-√2)
=-√2/2

x+1-x^2/(x-1)=[(x+1)(x-1)-x^2]/(x-1)=-1/(x-1)=1/(1-x)=1/(-√2)=-√2/2

x-1-x²/（x-1）=（x²-2x+1-x²）/（x-1）=（1-2x）/（x-1）。当x=根2-1时，原式=（3根2-4）/2.。