已知sin(3π-α)= √2sinβ,√3cos(-α)=- √2cos(π+β),0

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已知sin(3π-α)= √2sinβ,√3cos(-α)=- √2cos(π+β),0
已知sin(3π-α)= √2sinβ,√3cos(-α)=- √2cos(π+β),0

已知sin(3π-α)= √2sinβ,√3cos(-α)=- √2cos(π+β),0
sin(3π-α)= √2sinβ,
sin(2π+π-α)= √2sinβ,
sin(π-α)= √2sinβ,
sinα= √2sinβ
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