mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗?但用/.带进去算输出不是零是什么问题?

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 16:49:36

mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗?但用/.带进去算输出不是零是什么问题?
mathematica 解方程
Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) -
cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]
我这样写对吗?但用/.带进去算输出不是零是什么问题?

mathematica 解方程Solve[cos (6^(1/2)/3*(t + t3/2))*sin (6^(1/2)/3*t3/2) - cos (6^(1/2)/3*(t + t2 + t3 + t1/2))*sin (6^(1/2)/3*t1/2) == 0,t]我这样写对吗?但用/.带进去算输出不是零是什么问题?
首先,不符合基本语法.可以写成这样的形式:
Solve[Cos@(6^(1/2)/3*(t + t3/2))*Sin@ (6^(1/2)/3*t3/2) -
Cos@ (6^(1/2)/3*(t + t2 + t3 + t1/2))*Sin@(6^(1/2)/3*t1/2) == 0, t]
然后求解我就没法帮了,里面的t1,t2,t3是你之前的赋值吧?欢迎追问