If an electron loses 2.5E-15 J of energy in travelling from the cathode to the screen in a home computer,across what potential difference must it travel?

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If an electron loses 2.5E-15 J of energy in travelling from the cathode to the screen in a home computer,across what potential difference must it travel?
If an electron loses 2.5E-15 J of energy in travelling from the cathode to the screen in a home computer,across what potential difference must it travel?

If an electron loses 2.5E-15 J of energy in travelling from the cathode to the screen in a home computer,across what potential difference must it travel?
“电势”升高,电势差为:
U=W/q=(2.5E-15)J/(1.6E-19)C=15625V=15.625KV

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