1.2345^2+0.7655^2+2.496*0.7655注:此题中"2"指平方.

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1.2345^2+0.7655^2+2.496*0.7655注:此题中"2"指平方.
1.2345^2+0.7655^2+2.496*0.7655
注:此题中"2"指平方.

1.2345^2+0.7655^2+2.496*0.7655注:此题中"2"指平方.
4.0206685

1.2345^2+0.7655^+2.496*0.7655
=(1.2345+0.7655)^2-2*1.2345*0.7655+2.496*0.7655
=4-(2.469-2.469)*0.7655
=4
其实这个题目就只是考你这个公式的应用:
(a+b)^2=a^2+2ab+b^2

(1+0.2345)(1+0.2345)+(1-0.2345)(1-0.2345)+2.496*(1-0.2345)
=1+2*0.2345+0.2345*0.2345+1-2*0.2345+0.2345*0.2345+2.496-2.496*0.2345
=4.496+2*0.2345*0.2345-2.496*0.2345
=4.496+0.2345(0.469-2.4...

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(1+0.2345)(1+0.2345)+(1-0.2345)(1-0.2345)+2.496*(1-0.2345)
=1+2*0.2345+0.2345*0.2345+1-2*0.2345+0.2345*0.2345+2.496-2.496*0.2345
=4.496+2*0.2345*0.2345-2.496*0.2345
=4.496+0.2345(0.469-2.496)
=4.496-2.027*0.2345
=4.0206685???
检查一下你的题目,应该有点问题,是不是把2.469写成2.496呢?
如果题目原本是2.469,那结果很容易算,结果是4.

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