因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方.

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因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方.
因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2
x,y,后的2为平方.

因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方.
x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2
=x^4-2x^2y^2+y^4+z^4-2x^2z^2-2y^2z^2
=(x^4-2x^2y^2+y^4)+(z^4-2x^2z^2-2y^2z^2)
=(x^2-y^2)^2+z^4-2y^2z^2+2z^2x^2-4z^2x^2
=(x^2-y^2)^2+2z^2(x^2-y^2)+z^4-4z^2x^2
=(x^2-y^2+z^2)^2-4z^2x^2
=(x^2-y^2+z^2+2zx)(x^2-y^2+z^2-2zx)
=[(x+z)^2-y^2][(x-z)^2-y^2]
=(x+y+z)(x-y+z)(x+y-z)(x-y-z)

x^4 + y^4 + z^4 - 2x^2y^2 - 2x^2z^2 - 2y^2z^2
=[z^2 - (x+y)^2][z^2 - (x-y)^2]
=(z + x + y)(z - x - y)(z + x - y)(z - x + y)

因式分解：x4+y4+z4-2x2y2-2y2z2+2z2x2 因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方. 因式分解：x4+y4+z4-2x2y2-2y2z2-2z2x2 最好能有详细过程,谢谢 4x4+5x2y2+7xy3+2y4怎么因式分解? 证明;x4+y4+z4-2x2y2-2x2y2-2y2z2能被（x+y+z）整除 x4-7x2y2+9y4因式分解因式分解x4-7x2y2+81y4 x4-2x4y4+y4因式分解证明:x4+y4+z4-2x2y2-2x2z2-2y2z2能被x+y+z整除八年级寒假作业题目因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1 因式分解x4(y2-z2)+y4(z2-x2)+z4(x2-y2).数字是字母的指数, 因式分解,x4-7x2y2+y4=?x4-7x2y2+y4=?应该是(x2+?xy+y2)(x2-?xy+y2) 的形式,那个?是多少因式分解：x4次方-2x²y²+y4次方因式分解 X4次方+y4次方-2X2次方y2次方已知x+y+z=0,求x4+y4+z4-2x2y-2y2z2-2z2x2的值有指数 x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,x4+y4+z4=? x4+y4因式分解因式分解：(x+y+z)4-(y+z)4-(z+x)4-(x+y)4+x4+y4+z4,