已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 18:36:48

已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由
已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式
已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由

已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由
A=3x^2-12
=3(x^2-4)
=3(x-2)(x+2)
B=5x^2*y^3+10x*y^3
=5xy^3(x+2)
C=(x+1)(x+3)+1
=x^2+4x+3+1
=x^2+4x+4
=(x+2)^2
公因式=x+2

已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由 1、(-y^3)^5/y^3/ y^2+2(-y)^102、(x-y)^7/(y-x)^6+(x+y)^3/(x+y)^23、已知X^a=5,x^b=3,求X^(3a-2b)的值 已知:A=X*X-3xy+y*y,B=2x*x+xy-3y*3y.求A+B,A-B,A+2B 已知集合A={(x.y)|5x-3y=3},B={(x.y)|2x+4y=5}求A交B 已知集合A={(x,y)|3x-7y=-5},B={(x,y)|2x+9y=40},求A∩B(用列举 已知集合a(x,y)2x-y-5=0 b(x,y)x+3y+1=0 求A∩B 具体步骤 已知集合a(x,y)2x-y-5=0 b(x,y)x+3y+1=0 求A∩B 已知3x+2y=a,2x+3y=b,则(x+y)(x-y)=? 已知集合A={y=x^2-2x-3},B={x|x^2+4x-5 已知a/b=2/3,求 a+b/b?已知x²=3,求 x+x/1/x-x/1?(x减x分之一 分之 x加八分之一)已知x/y=3,求 x²+2xy-3y²/x²-sy+y²?已知1/x+1/y=5,求 2x-3xy+2y/x+2xy+y?已知x²+3x+1=0,求 x²+1/x²? 已知2A-B=x,2B-A=y,求3A+5B 已知(a^2*b)^x*(a^x-1*b^2-y)^5=x^12*y^10,求x,y 的值 初一因式分解练习题,谁好心帮我解下表示平方1.2X~-3XY-X2.(X+Y)~(X+Y)(X-Y)(X+Y)(Y+Z)3.3X(a+2b)~-6XY(a+2b)4.a(x-y)-b(X-Y)-C(Y-X)5.(b-a)~-2a+2b6.(x-y)~-m(y-x)+y-x7.x(x-y)(a-b)-y(y-x)(b-a)8.已知a+b=13,ab=40,求 b+ab~的值 几道比例线段题目已知两实数a,b满足a^2-4ab+4b^=0,求(a+b)/a已知x/2=y/3,求(x-y)/y ,(x+y)/y ,(x+y)/(x-y) 1)已知4X=5y,求(X+y):y 2)已知(a-b):(a+b)=3:7,求a:b 已知5^x=a,5^y=b,试用a,b表示5^2x-3y 已知x+y=a,x-y=b.求:x^2+y^2;xy 已知2a+b=4,求代数式(2a+b)二次方-12/4a+2b已知2x-y/x+3y=2,求代数式4x-2y/x+3y - 4x+12y/2x-y已知2a+b=4,求代数式(2a+b)²- 12/4a+2b