(Log(4)3+log(8)3)(log(3)2+log(9)2) 顺便问下lg3乘lg4=lg（3+4）?

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(Log(4)3+log(8)3)(log(3)2+log(9)2) 顺便问下lg3乘lg4=lg（3+4）?
(Log(4)3+log(8)3)(log(3)2+log(9)2) 顺便问下lg3乘lg4=lg（3+4）?

(Log(4)3+log(8)3)(log(3)2+log(9)2) 顺便问下lg3乘lg4=lg（3+4）?
(Log(4)3+log(8)3)(log(3)2+log(9)2)
=[(1/2)log2[3]+(1/3)log2[3]][log3[2]+(1/2)log3[2]]
=(5/6)log2[3]*(3/2)log3[2]
=(5/4)[(ln3/ln2)*(ln2/ln3)]
=5/4
lg3*lg4≠lg(3+4)
lg3+lg4=lg(3*4)=lg12

用换底公式：logaN =logbN/logba （N>0,a>0且a≠1，b>0且b≠1）其中logaN表示以a为底N的对数。
原式=(log23/log24+log23/log28)(log22/log23+log22/log29)
= (log23/2+log23/3)(1/log23+1/2log23)
=5log23/6*3/2log23
=5/4
lg3*lg4≠lg(3+4)
公式lg（ab）=lga+lgb (a，b>0)

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