求X,x is in radians1）sin^2x- cosx =12）2sin^2-tanxcosx-1 =0

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求X,x is in radians1）sin^2x- cosx =12）2sin^2-tanxcosx-1 =0
求X,x is in radians
1）sin^2x- cosx =1
2）2sin^2-tanxcosx-1 =0

求X,x is in radians1）sin^2x- cosx =12）2sin^2-tanxcosx-1 =0
1）sin²x- cosx =1
1-cos²x-cosx=1
cosx(cosx+1)=0
cosx=0,cosx=-1
x=kπ+π/2,x=2kπ+π
2）2sin²x-tanxcosx-1 =0
2sin²x-(sinx/cosx)cosx-1=0
2sin²x-sinx-1=0
(2sinx+1)(sinx-1)=0
sinx=-1/2,sinx=1
sinx=1时x=2kπ+π/2
此时tanx无意义
所以sinx=-1/2
x=2kπ-5π/6,x=2kπ-π/6

(1)sin^2x- cosx
=1-cos^2x-cosx
=1
所以-cos^2x-cosx=0
则cosx=0或-1
x=π/2或π
（2）2sin^2x-tanxcosx-1
=2sin^2x-sinx-1=0
所以sinx=1或-1/2
x=π/2（舍）或5π/6

1）sin^2x-cosx=sin^2x+cos^2x
cox(1-cosx)=0
x=π/2+kπ 或 x=2kπ
2）
2sin^2x-tanxcosx-1=0
2sin^2x-sinx-1=0（cosx≠0）
（2sinx+1)（sinx-1）=0
sinx=-1/2 或sinx=1（舍去）
x=-π/6+2kπ 或x=-5π/6+2kπ

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