Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注：这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val

Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注：这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val
Exercise 1.Consider the following system of linear equations where a is a number:
2x + 3y - z = a
-4x - 6y = a
-x- z = a
注：这仨是个方程组 大括号打不进来
a) For what values of a does the system above have a unique solution?
b) For what values of a the system above does not have a solution?
c) What is the solution to the system above if a =
d) What is the solution to the system above if a = 3/2?
Exercise 2 a) Solve the following maximization problem x; y \x15 0:
maxx,y u(x,y) =1/3lnx +2/3lny
s.t.3x + 2y = 24
注：方程组
b) Solve the following maximization problem for x; y \x15 0:
maxx,y u(x,y) = min｛2x -y; 5x - 2y｝
s.t.x + y = 5
注：方程组
where min｛a,b｝ is the minimum number between a and b.Thus,for instance:min｛5,4｝ =4,min｛-2,-7｝ = -7,min｛2x,4x｝ = 2x if x \x15大于等于0 and min｛2x,4x｝ = 4x if x 小于等于\x14 0,etc.
不好意思 第一题 最后一个方程 弄错了 应该是 -x-z= a2 a的平方！

Exercise 1.Consider the following system of linear equations where a is a number:2x + 3y - z = a-4x - 6y = a-x- z = a注：这仨是个方程组 大括号打不进来a) For what values of a does the system above have a unique solution?b) For what val
x=1/2a.y=-1/2a,z=-2/3a,在分析a的值就行了啊

能不能问一下你用的这本英文版高中数学课本的具体信息吗？具体名称、出版社，编者等能不能跟我说一下呢？

先求方程的解x=-a的平方+3a,y=2/3a的平方-13/6a,z=-3a.先求前两个，三角形>0,有两个不等实数根，求出三角形=零，就只有一个实数根，就求出唯一的解了。第二小道题正好三角形>0就行了。我找不到三角形那个符号，希望您能理解不好意思 第一题 最后一个方程 弄错了 应该是 -x-z= a2 a的平方！ 所以X不等于-a的 您会第二题么。。。...

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先求方程的解x=-a的平方+3a,y=2/3a的平方-13/6a,z=-3a.先求前两个，三角形>0,有两个不等实数根，求出三角形=零，就只有一个实数根，就求出唯一的解了。第二小道题正好三角形>0就行了。我找不到三角形那个符号，希望您能理解

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you can use Lagrange multiplier to solve 2, 3. 1 is easy.

你告诉我maxx,y u(x, y)什么意思我绝对可以帮你解出来

第一题任何时候都有唯一解

我英语看这个有点蛋疼