化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 07:43:43

化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]

化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
=-cosx×sinx/[-sin(180°+x)][cos(180°+x)]
=-cosx×sinx/sinx(-cosx)
=1