lim[(a-cosx)/ln(1-x)]=0求a的值

lim(x->0)(ln(1+x)-x)/(cosx-1)=? lim[(a-cosx)/ln(1-x)]=0求a的值 lim(x→0)(cosx)^(1/ln(1+x^2)) lim (cosx)^ln(1/1+x^2)怎么算 lim(x趋向0)(e-e^cosx)/ln(1+x2) 求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx lim(x趋于0+)(ln(xln a)ln(ln ax/ln(x/a))),其中a>1 lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少? lim x趋于0 (sinx+x^2sin1/x)/[(1+cosx)ln(1+x)] 求极限lim(cosx-e^-x^2/2)/x^2[2x+ln(1-2x)] lim/x-0(cosx)/ln(1+x^2)求极限x-0表示x趋于0 lim(1-cosx)/(e^x-1)ln(1-x),x->0题没有错 lim(x趋于0)（1-cosx）/[ln(1+x)(e^x-1)] 求极限:lim(x趋于0)（1-cosx）/[ln(1+x)(e^x-1)] lim(x趋于0)（1-cosx）/[ln(1+x)(e^x-1)] x趋向于0,lim[x*ln(1+3x)]/(1-cosx) x→0,lim(1-cosx)[x-ln(1+tanx)]/sinx^4的极限 求极限lim(x→0)][ln(1+2x^2)+n sinx]/(1-cosx)