初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1[x+1/(x-1)]+[2/(x+2)]=1

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初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1[x+1/(x-1)]+[2/(x+2)]=1
初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1
[x+1/(x-1)]+[2/(x+2)]=1

初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1[x+1/(x-1)]+[2/(x+2)]=1
两边乘(x-1)(x+2)
x²+3x+2+2x-2=x²+x-2
5x=x-2
x=-1/2
经检验,x=-1/2是方程的解

在分式方程两边同乘(x-1)(x+2)
得:(x+1)(x+2)+2(x-1)=(x-1)(x+2)
化简得:x²+3x+2+2x-2=x²+x-2
解得:x=-1/2
经检验,x=-1/2是方程的解

x2+5x=x2+x-2

4x=-2

∴x=-1/2

经检验,x=-1/2是原方程的解

(x+1)/(x-1)=1-2/(x+2)
(x+1)/(x-1)=x/(x+2)
x2-x=x2-3x+2
x=-1/2
检验x=-1/2是原方程的根