1/2△1/3=1/2*5+1/3*3=3又1/2 1/5△2/9=1/5*5+2/9*3=1又2/3 ①m△n=m*()+n*() ②若x△5/12=2,求x

题目是若1△=1 2△=1+1/2 3△=1+1/2+1/3 4△=1+1/2+1/3+1/4 5△=1+1/2+1/3+1/4+1/5 求6△-5△= 1△4=1234,2△3=234,3△2=34,那么4△5=? 定义一种新的运算符号“△” 2/3△1/5=2/3×3-1/5×2;1.5△1/4=1.5×3-1/4×2；30%△1/3=30%×3-1/3×2计算：（5/6△1/4）△6/1前面的错了 订 计算：（5/6△1/4）△1/6 1+2+3-4-5+1+1+2+3= 7△4=4的平方+1求(-5)△3=?(-2)△(3△2)=? 规定1/2△3=1/2*2/3*3/4,1/7△4=1/7*2/8*3/9*4/10,那么求1/2△4-1/5△3的值 若规定1/2△3=1/2*2/3*3/4,1/7△4=1/7*2/8*3/9*4/10,求1/2△4+1/5△3的值 已知1△3=1×2×3,3△5=3×4×5×6×7,那么8△3=? 1 2 3 4 5=1 1()2()3()4()5=1 1+1-2+3-4+5=? 1/2△1/3=1/2*5+1/3*3=3又1/2 1/5△2/9=1/5*5+2/9*3=1又2/3 ①m△n=m*()+n*() ②若x△5/12=2,求x 巧算：(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)===== -5X-2/1=3/1(X-3/1) 3+1/2+1/3+1/4+5=? 求和Sn=1*(1/3)+3*(1/3)^2+5*(1/3)^3+.+(2n-1)*(1/3)^n求和Sn=1*(1/3) + 3*(1/3)^2 + 5*(1/3)^3 +.+(2n-1)*(1/3)^n 1+3-5*4^2-3= 计算(+5/2)-(-5/3)=-5/1(-5/2)-(-5/3)=5/12/1-3/1=6/1(-2/1)-3/1=-6/1