(英文题)

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(英文题)
(英文题)
 

(英文题)
2(a):a1=(vt-v0)/(t1-t0)=6m/s / 3s = 2m/s2
2(b):a2=(vt-v0)/(t1-t0)=(10m/s-4m/s) / 3s = 2m/s2
2 ( c ):s = (a1*t1*t1)/2 + v5*t2 = (2*5*5)/2+10*1 = 35m

第一题第一问 1/2*g*t²=420米 可以算出t
第二问v²=2gs可以算出v

1、
(a)h=gt²/2 420=0.5*9.8*t² t=9.26s
(b)v=√(2gh)=√(2*9.8*420)=90.7m/s
2、
(a)6/3=2m/s²
(b)(10-4)/4=1.5m/s²
(c)Calculate the area between the line and the...

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1、
(a)h=gt²/2 420=0.5*9.8*t² t=9.26s
(b)v=√(2gh)=√(2*9.8*420)=90.7m/s
2、
(a)6/3=2m/s²
(b)(10-4)/4=1.5m/s²
(c)Calculate the area between the line and the time axis
s=5*10/2+1*10=35m
3、
(a)h=gt²/2 350=9.8t²/2 t=8.45s
(b)
(c)Vy=gt=9.8*8.45=82.81m/s
V=√(Vx²+Vy²)=√(52²+82.81²)=97.8m/s

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