已知5x2-6xy+2y2-4x+2y+1=0,求x、y的值

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已知5x2-6xy+2y2-4x+2y+1=0,求x、y的值
已知5x2-6xy+2y2-4x+2y+1=0,求x、y的值

已知5x2-6xy+2y2-4x+2y+1=0,求x、y的值
5x^2-6xy+2y^2-4x+2y+1=0
(3x-y)^2-4x^2-4x-1+y^2+2y+1=-1
3(x-y)^2+1+(y+1)^2=(2x+1)^2
x=-1
3(1+y)^2+(y+1)^2=0
y=-1
方程解x=-1,y=-1

参看http://zhidao.baidu.com/question/222885433.html

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