已知 log2(3)=A log3(7)=B 试求log14(56)

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已知 log2(3)=A log3(7)=B 试求log14(56)
已知 log2(3)=A log3(7)=B 试求log14(56)

已知 log2(3)=A log3(7)=B 试求log14(56)
运用换底
log14(56)
=log3(56)/log3(14)
=log3(7*8)/log3(2*7)
=〔log3(7)+log3(8)〕/〔log3(7)+log3(2)〕
log3(2)=1/log2(3)=1/a
log3(8)=3log3(2)=3/a
log14(56)
=(b+3/a)/(b+1/a)
=(ab+3)/(ab+1)
=1+2/(ab+1)

由log2(3)=A得lg2/lg3=A 由log3(7)=B得lg3/lg7=B
两式相乘得lg7/lg2=AB,所以lg7=ABlg2
log14(56)=lg56/lg14=(lg7+2lg2)/(lg2+lg7)
把lg7=ABlg2代入得log14(56)=(AB+2)/(AB+1)