80℃ 时,0.01mol/l的盐酸pH=,

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80℃ 时,0.01mol/l的盐酸pH=,
80℃ 时,0.01mol/l的盐酸pH=,

80℃ 时,0.01mol/l的盐酸pH=,
溶液的PH值,只与溶液中氢离子浓度有关
所以80℃ 时,0.01mol/l的盐酸pH=-lgC(H+)=-lg0.01=2

0.01mol/l的盐酸pH=-lg0.01=2