p=1 For k From 1 To 10 Step p=p+2*k-6 End For Print p

p=1 For k From 1 To 10 Step p=p+2*k-6 End For Print p For K=1 TO 20 For K=1 TO 20 SET TALK OFF CLEAR STORE 0 TO S,T,P FOR K=1 TO 10 DO ... SET TALK OFF CLEAR STORE 0 TO S,T,P FOR K=1 TO 10 DO CASE CASE INT(K/2)=K/2 T=T+K CASE INT(K/5)=K/5OTHERWISE P=P+KEND CASEENDFORK,T,S,PSET TALK OFF vfp中K!+(K+1)!+……M!里面的!下面程序的执行流程：clearinput请输入K值： TO Kinput请输入M值： TO Ms=0for r =k to mdo sub with a,rs=s+aendforS的值为：,sreturnprocedure subparameters p,np=1for l=1 to np=p*lendforreturn 一道matlab不动点迭代求高手指点function [k,p,err]=fixpt(g,p0)P(1)=p0;tol=1.e-8;max1=50;for k=2:max1P(k)=feval(g,P(k-1));err=abs(P(k)-P(k-1));relerr=err/(abs(P(k))+eps);p=P(k);if(err If f is the function defined for all k by f(k) = k^5/16,what is f(2k) in terms of f(k)?A.1/8 f(k)B.5/8 f(k)C.2 f(k)D.10 f(k)E.32 f(k)标答是D,但我怎么求都是E另外一道,If an integer n is to be chosen at random from the integers 1 to 96,inc 、这段lingo代码什么意思 @for(points(p):@sum(points(i)|i#ne#p:@sum(cars(k):x(i,p,k)))=1;@sum(points(j)|j#ne#p:@sum(cars(k):x(p,j,k)))=1;); VB题 a=5 For k=1 To 0 a=a+k Next k Print k；a pascal :got boolean expected longintvar n,p,q,i,k,j:longint;t2:boolean; t1:boolean ;beginreadln(n);p:=1;repeatp:=p+1;q:=n-p;t1:=true;for i:=2 to trunc(sqrt(p)) doif p mod j=0 then begin t1:=false; k:=k+1;end;t2:=true;for i:=2 to trunc(sqrt(q)) do 求解释matlab程序啊,越详细越好,function [Rx2,Rx22] = cyclic_xcorr(Rx,P,k_len,tao_len)Rx2 = zeros(2*k_len*P-1,2*tao_len*P-1);for k = 1-k_len*P :k_len*P-1for tao = 1-tao_len*P :tao_len*P-1for n = 0 :P-1Rx2(k+k_len*P,tao+tao_len*P) = Rx2(k+k_l For n From 3 To 10 和For n From 1 To 8.意思一样吗? 输入n,m k=1,p=1 p=p(n-m+k) k 请看以下的程序填空main(){ int k,p;int s[]={1,-9,7,2,-10,3}for (p=0,k=p;ps[k]) __________printf(%d ,k);}` main() {int j,k,p,s; s=0; for(j=1;j LINGO 运行显示错误70：下标越界,@for(rp(r):@sum(link1(j,l):x(r,j,l))=z(j,l)));@for(p(k):n(k)*(1-y1(k))=it1(k,k));@for(rp(r):@sum(p(k):it2(k,r)) matlab怎么求均值for k=0:100;p='(1-(3/4)*((1-p)^k))/k';p=vectorize(p);p=eval(p);end每个K都对应一个P值,怎么求这些P的均值呢?能用小数表示吗?