用matlab解决设r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10,计算x(t),y(t),

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用matlab解决设r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10,计算x(t),y(t),
用matlab解决设r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10,计算x(t),y(t),

用matlab解决设r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10,计算x(t),y(t),
能否将题目说的详细点?我怎么看不懂,不明白x(t),y(t)与r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10有什么关系.

用matlab解决设r1=r2=1,n1=n2=100,m1=0.5,m2=2,x10=x20=10,计算x(t),y(t), matlab 微分方程求解作图这个方程怎么解,还有图象怎么出来~dN1/dt=[r1*(1-N1/K1)-m*N2]*N1;dN2/dt=[r2*(1-N2/K2)-n*N1]*N2;其中r1=0.01,r2=0.05,K1=1000,K2=1000,m=9e-6,n=4e-5;N1(0)=0,N2(0)=0. MATLAB用fsolve解方程H=1.90;lanmuda=1.55;n1=1.55;n2=1.67;n3=1.50;k0=2*pi/lanmuda;r1=sqrt(n^2-n1^2)*k0;r2=sqrt(n2^2-n^2)*k0;r3=sqrt(n^2-n3^2)*k0;fun=@(n)(r2*H-atan(r1/r2)-atan(r3/r2))s= fsolve(fun,1.60)错误信息如下:fun = @(n)(r2*H-atan(r1/r matlab求方程.方程组如下:a*r1=arctan(r2/r1)r1^2+r2^2=k0^2(n1^2-n2^2) 其中:a=2 k0=2pi/0.6328 n1=1.568 n2=1.538r1 r2我按百度的教程一直都是无解, 在公式1/R=1/r1+1/r2中(r1+r2≠0),用r1,r2表示R是? 在公式1/R=1/r1+1/r2中(r1+r2≠0),用r1、r2表示R是 已知1/R=R1+R2/R1R2,R1≠R2,用R、R1的分式表示R2 MATLAB方程求解问题clearsyms n H=1.60;lanmuda=1.55;n1=1.55;n2=1.67;n3=1.5;k0=2*pi/lanmuda;c1=n2^2/n1^2;c2=n2^2/n3^2;r1=sqrt(n.^2-n1^2)*k0;r2=sqrt(n2^2-n.^2)*k0;r3=sqrt(n.^2-n3^2)*k0; fun=r2*H-atan(1.1608*r1/r2)-atan(1.2395*r3/r2)solve(fun==0,n) R1+R2=1000,1/R1+1/R2=1/160,请问R1,R2分别是多少? (r1+r2)^2-(1.5-r1-r2)^2-(1-r1-r2)^2=0 若1/R1+1/R2=1/R,用R、R1表示R2,应为? 请用MATLAB解下面方程组.[r1,r2,a1,a2,B]=solve('670=(r1+1)*a1+(r2+1)*a2+2*160*cos(B)','sin(B)=(r2-r1)/160','1=r2/r1','a1+a2=2*pi','a1=pi-2*(r2-r1)/160')直接解出来结果是:r1 =0pir2 =pipia1 =pipia2 =-(pi-175)/pi-(pi-495)/piB =-(pi-175)/p 1/R=1/R1+1/R2 R=R1+R2/R1 R2 R=R1 R2/R1+R2 这三种关于并联电路的电阻公式 MATLAB解方程问题syms n lanmuda=1.55;n1=1.6375696780514445567155543374853;n2=1.6443618413936927969908352393948;n3=1.6375696780514445567155543374853;c1=n2^2/n1^2;c2=n2^2/n3^2;k0=2*pi/lanmuda;r1=sqrt(n.^2-n1^2)*k0;r2=sqrt(n2^2-n.^2)*k0;r3=sqrt(n.^2 R1R2/R1+R2=? R1:R2=1:4; 为什么R总=R1R2/R1+ R2=R2/5 R1:R2=3:1 R2:R3=2:3 求R1:R2:R3 1/R=1/R1+1/R2(R1≠R2)则表示R1的式子是