记算:(m+1)(m-1)(m的平方-1)

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记算:(m+1)(m-1)(m的平方-1)
记算:(m+1)(m-1)(m的平方-1)

记算:(m+1)(m-1)(m的平方-1)
(m+1)(m-1)(m²-1)
=(m²-1)(m²-1)
=m的4次方-2m²+1

:(m+1)(m-1)(m²-1)=(m²-1)(m²-1)=(m²-1)²

(m+1)(m-1)(m^2-1)=(m^2-1)^2=m^4-2m^2+1(^是成方的意思)

(m+1)²-9(m-1)
=(m+1)²-[3(m-1)]²
=[(m+1)-3(m-1)][(m+1)+3(m-1)]
=(m+1-3m+3)(m+1+3m-3)
=(4-2m)(4m-2)
=2(2-m)(2m-1)