等比数列an中a3=7,前三项和s3=21a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;我想问(2)/(1)得 1+q+q^2/q^2=3然后怎么算?

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等比数列an中a3=7,前三项和s3=21a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;我想问(2)/(1)得 1+q+q^2/q^2=3然后怎么算?
等比数列an中a3=7,前三项和s3=21
a3=a1*q^2=7; (1)
s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)
(2)/(1)得
q=1,或q=-1/2;
我想问(2)/(1)得 1+q+q^2/q^2=3然后怎么算?

等比数列an中a3=7,前三项和s3=21a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;我想问(2)/(1)得 1+q+q^2/q^2=3然后怎么算?
(2)/(1)得 (1+q+q^2)/q^2=3
1+q+q^2=3q^2
2q^2-q-1=0
(q+1)*(2q-1)=0
q=1,或q=-1/2;

若q为1,则a1=a2=a3=7, an=7。若q=-0.5,由a1q²=7,得a1=28,则an=28x(-0.5)的n次方