求函数Z=x^xy的偏导数答案是Z=f'x(x,y)=yx^xy(lnx+1),Z=f'y(x,y)=x^(xy+1)lnx,
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求函数Z=x^xy的偏导数答案是Z=f'x(x,y)=yx^xy(lnx+1),Z=f'y(x,y)=x^(xy+1)lnx,
求函数Z=x^xy的偏导数
答案是Z=f'x(x,y)=yx^xy(lnx+1),Z=f'y(x,y)=x^(xy+1)lnx,
求函数Z=x^xy的偏导数答案是Z=f'x(x,y)=yx^xy(lnx+1),Z=f'y(x,y)=x^(xy+1)lnx,
Z=f'x(x,y)=xy*[x^(xy-1)]*y
Z=f'y(x,y)=xy*[x^(xy-1)]*x
自变量在指数上的,简单的方法是取对数,相信见到过这种方法奥麻烦写一下过程吧想问一下是Z=y*x^x ?若是,则 两边取对数 lnZ=xlnx+lny, 对x取偏导 Zx/Z=lnx+1 两边同时乘以Z Zx=Z(lnx+1)=yx^x(lnx+1) 对于y的偏导数直接求就可以了 Zy=x^x是Z=x^xy是Z=x^(xy)吧?若是 两边去对数 lnZ=lnZ(x,y)=xyln...
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自变量在指数上的,简单的方法是取对数,相信见到过这种方法奥
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z = x^(x y)
lnz = xylnx
(1/z)f'x(z) = xy(1/x) + (lnx) (y)
= y+ylnx
f'x(z) = (1+lnx)z = y(1+lnx)(x^(xy))
lnz = xylnx
(1/z) f'y(z) = xlnx
f'y(z) = z(xlnx) =(z...
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z = x^(x y)
lnz = xylnx
(1/z)f'x(z) = xy(1/x) + (lnx) (y)
= y+ylnx
f'x(z) = (1+lnx)z = y(1+lnx)(x^(xy))
lnz = xylnx
(1/z) f'y(z) = xlnx
f'y(z) = z(xlnx) =(z^(xy) ) xlnx
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