已知2x+3y+z=130,3x+5y+z=180,试求x+2y/x+y+z的值

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已知2x+3y+z=130,3x+5y+z=180,试求x+2y/x+y+z的值
已知2x+3y+z=130,3x+5y+z=180,试求x+2y/x+y+z的值

已知2x+3y+z=130,3x+5y+z=180,试求x+2y/x+y+z的值
2x+3y+z=130
4x+6y+2z =260
用4x+6y+2z =260 减去 3x+5y+z=180得到:
(4x+6y+2z )- (3x+5y+z)=260-180
x+y+z =80
用3x+5y+z=180 减去 2x+3y+z=130 得到:
x+2y =50
所以:x+2y/x+y+z =50/80 =5/8

2x+3y+z=130
4x+6y+2z =260
用4x+6y+2z =260 减去 3x+5y+z=180得到:
(4x+6y+2z )- (3x+5y+z)=260-180
x+y+z =80
用3x+5y+z=180 减去 2x+3y+z=130 得到:
x+2y =50
所以:x+2y/x+y+z =50/80 =5/8

∵2X+3Y+Z=130 ①
3X+5Y+Z=180 ②
∴②-①得:X+2Y=50
①*2-②得:X+Y+Z=80
∴X+2Y/X+Y+Z=50/80=0.625