x^2-xy-2y^2-x+5y-2

来源：学生作业帮助网编辑：作业帮时间：2024/04/29 08:03:22

x^2-xy-2y^2-x+5y-2
x^2-xy-2y^2-x+5y-2

x^2-xy-2y^2-x+5y-2
首先,X^2-XY+2Y^2=(X-2Y)(X+Y)
所以,设x^2-xy-2y^2-x+5y-2可分解成
(X-2Y+A)(X+Y+B)
则展开有X的一次项=A+B=-1
Y的一次项有A-2B=5
连列成方程,解出A=1 B=-2
所以有原式可以分解为:(X-2Y+1)(X+Y-2)

x^2-xy-2y^2-x+5y-2
=(x-2y)(x+y)-x+5y-2
=(x-2y)(x+y)+(x+y)-2x+4y-2
=(x+y)(x-2y+1)-2(x-2y+1)
=(x+y-2)(x-2y+1)

(-x-y)(x^2+xy+y^2) 化简x^-y^/x^-2xy+y^ 2*(x-y)²(y-x)(xy) （x^2+xy/x-y)/（xy/x-y)计算因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6 X-Y/2X+2Y XY/X+Y² 因式分解：x×x-xy-2y×y-x-y 化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy] 因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) (x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy] .(x+y-2)(x+y-2xy)+(xy-1)^2 (x^2-xy)y÷y-x/xy怎么做? 代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy (x+y)/x /(x-(2xy-y^2)/x) 因式分解 x^2-xy-2y^2-x+5y-2 -x^5y-xy+2x^3y 2X^+XY-Y^-4X+5Y-6 2x^+xy-y^-4x+5y-6=?