[(x-3)/(x-7)]+1=(x-5)/(x-4),求x的值.

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[(x-3)/(x-7)]+1=(x-5)/(x-4),求x的值.
[(x-3)/(x-7)]+1=(x-5)/(x-4),求x的值.

[(x-3)/(x-7)]+1=(x-5)/(x-4),求x的值.
化简为
[(x-1)(x-5)]/[(x-4)(x-7)]=0
x= 1或5