已知cos(π/2+a)=1/3 求tan(3π/2-a)cosa怎么求?

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已知cos(π/2+a)=1/3 求tan(3π/2-a)cosa怎么求?
已知cos(π/2+a)=1/3 求tan(3π/2-a)
cosa怎么求?

已知cos(π/2+a)=1/3 求tan(3π/2-a)cosa怎么求?
cos(π/2+a)=1/3
-sina = 1/3
sina = -1/3
tan(3π/2-a)
= tan(π/2-a)
= cota
= cosa/sina
= ±2√2/3

cos(π/2+a)=1/3
cos{π-(π/2-a)}=1/3
-cos(π/2-a)=1/3
-sina=1/3
sina=-1/3
tan(3π/2-a)
= tan{π+(π/2-a)}
= tan(π/2-a)
= cot a
= ±根号{1-sin^2a} /sina
= ±根号{1-(-1/3)^2} /(-1/3)
= ±2根号2