化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 11:47:19

化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]
化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]

化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]
sin(π-a)cos(3π-a)tan(-π-a)tan(a-2π)/tan(4π-a)sin(5π+a)
=sinacosatana/tanasina
=cosa