已知2tana×sina=3,-π/2<a<0,则cos(a-π/6)=

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已知2tana×sina=3,-π/2<a<0,则cos(a-π/6)=
已知2tana×sina=3,-π/2<a<0,则cos(a-π/6)=

已知2tana×sina=3,-π/2<a<0,则cos(a-π/6)=
2tana×sina=3
2sin^2a-3cosa=0
2cos^2a+3cosa-2=0
(2cosa-1)(cosa+2)=0
cosa=1/2,a=-π/3,cosa=-2(舍)
cos(a-π/6)= cos(-π/2)= 0

2tanasina
=2sina/cosa×sina
=2sin²a/cosa
=(2-2cos²a)/cosa
=3
2-2cos²a=3cosa
2cos²a+3cosa-2=0
(2cosa-1)(cosa+2)=0
cosa=1或cosa=-2(舍去)
-π/2<a<0,所以sina=-√3/2
cos(a-π/6)
= cosacosπ/6+sinasinπ/6
=1/2×√3/2+(-√3/2)×1/2
=0