A man sold two accesories at $120 each.He made a profit of 20% for one accesory but a loss of 20% for the other.Find the overall profit or loss from the two sales.翻译:一个男人卖了两个饰品,每个120元.其中一个饰品,他赚了20%.

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A man sold two accesories at $120 each.He made a profit of 20% for one accesory but a loss of 20% for the other.Find the overall profit or loss from the two sales.翻译:一个男人卖了两个饰品,每个120元.其中一个饰品,他赚了20%.
A man sold two accesories at $120 each.He made a profit of 20% for one accesory but a loss of 20% for the other.Find the overall profit or loss from the two sales.
翻译:一个男人卖了两个饰品,每个120元.其中一个饰品,他赚了20%.但另一个饰品,他亏损了20%.请找出两个销售的整体利润或亏损.
loss of $10.(整体亏损:10元)
但是我不知道它的作法.
希望数学高手给我它的算法,感激不尽啊!

A man sold two accesories at $120 each.He made a profit of 20% for one accesory but a loss of 20% for the other.Find the overall profit or loss from the two sales.翻译:一个男人卖了两个饰品,每个120元.其中一个饰品,他赚了20%.
两饰品成本:1.120除以120%=100
2.120除以80%=150
总亏损:总成本-总价=100+150-120-120=10

120*2-(120/1.2+120/0.8)=-10

赚的饰品成本:120/(1+20%)=100
亏的饰品成本:120/(1-20%)=150
总成本:100+150=250
亏250-(120+120)=10

算出两个商品的原价,一个是100,一个是150,就好了
120/(1+20%)=100;120/(1-20%)=150.

一个成本价x 赚了20% x(1+20%)=120 x=100
一个成本价y 亏损20% y(1-20%)=120 y=150
总成本 100+150=250
卖的价钱 120+120 =240
所以整体亏损250-240=10

120×2=240元 120÷(1+20%)= 100元 120÷(1-20%)=150元 240-(100+150)=-10元 答:亏了10元。

赚了20%的原价为:120除以120/100=100
亏了20%的原价为:120除以80/100=150
利润:赚了100X20%=20
亏了150-120=30
结论:30-20=10 亏损10元
假设两件商品原价都为100%,卖120元赚了20%的,120元就为原价的120%,所以要除以120%。

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赚了20%的原价为:120除以120/100=100
亏了20%的原价为:120除以80/100=150
利润:赚了100X20%=20
亏了150-120=30
结论:30-20=10 亏损10元
假设两件商品原价都为100%,卖120元赚了20%的,120元就为原价的120%,所以要除以120%。
卖120元亏了20%,120元就为原价的80%,所以要除以80%

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