(1+sin2x)/cos2x=tan(π/4+x)

(1+sin2x)/cos2x=tan(π/4+x)
(1+sin2x)/cos2x=tan(π/4+x)

(1+sin2x)/cos2x=tan(π/4+x)
(1+sin2x)/cos2x
=[1-cos(2x+π/2)]/sin(π/2+2x)
=2sin²(x+π/4)/[2sin(π/4+x)cos(π/4+x)]
=sin(x+π/4)/cos(x+π/4)
=tan(π/4+x)