作业帮(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
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(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
(x+y)(x+y+2xy)+(xy+1)(xy-1)
(x+y)(x-y)+4(y-1)
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
(x+y)(x+y+2xy)+(xy+1)(xy-1)
=(x+y)^2+2xy(x+y)+(xy)^2-1
=(x+y+xy)^2-1
=(x+y+xy+1)(x+y+xy-1)
(x+y)(x-y)+4(y-1)
=x^2-y^2+4y-4
=x^2-(y^2-4y+4)
=x^2-(y-2)^2
=(x+y-2)(x-y+2)
(x+y)(x+y+2xy)+(xy+1)(xy-1)
=(x+y)(x+y)+2xy(x+y)+(xy+1)(xy-1) 乘法分配律
2 2 2 2 2 2
=x +2xy+y +2x y+2xy +x y -1
(x+y)(x-y)+4(y-1)
2 2
=x -y +4y-4
.(x+y-2)(x+y-2xy)+(xy-1)^2
xy-1+x-y
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
计算3xy[2xy-x(y-2)+x-1]
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
x^2-xy/xy-y^2约分
（x^2+xy/x-y)/（xy/x-y)计算
1.（xy-1）^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
因式分解（x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式：(X+Y）*（X+Y+2XY）+（XY+1）*（XY-1）
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
已知x+y=1,xy=-2,则x²y+xy²-2xy