(40-x+2)除以(x+2)=3,求x是多少?

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(40-x+2)除以(x+2)=3,求x是多少?
(40-x+2)除以(x+2)=3,求x是多少?

(40-x+2)除以(x+2)=3,求x是多少?
(40-x+2)/(x+2)=3
两边同乘(x+2),得:40-x+2=3(x+2)
化简,得:42-x=3x+6
移向,得:-4x=-36
系数化为1,得:x=9
∴x=9

(40-x+2)除以(x+2)=3
3(x+2)=40-x+2
3x+6=42-x
4x=36
x=9