怎么用C语言通过角速度求出角度?求个函数~~~rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: -1rate: 1rate: 0rate: 0rate: 7rate: 4rate: 0rate: 4rate: 4rate: 0rate: 0rate: 1rate: 0rate: 0rate: 0rate: 3rate: 1rate: 1rate: 0r

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怎么用C语言通过角速度求出角度?求个函数~~~rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: -1rate: 1rate: 0rate: 0rate: 7rate: 4rate: 0rate: 4rate: 4rate: 0rate: 0rate: 1rate: 0rate: 0rate: 0rate: 3rate: 1rate: 1rate: 0r
怎么用C语言通过角速度求出角度?求个函数~~~
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: -1
rate: 1
rate: 0
rate: 0
rate: 7
rate: 4
rate: 0
rate: 4
rate: 4
rate: 0
rate: 0
rate: 1
rate: 0
rate: 0
rate: 0
rate: 3
rate: 1
rate: 1
rate: 0
rate: 1
rate: 0
rate: 1
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 30
rate: 20
rate: 0
rate: 0
rate: 0
rate: 1
rate: 0
rate: 1
rate: 0
rate: 0
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 0
rate: 1
rate: 0
rate: 0
rate: 2
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: -1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: 1
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 0
rate: 1
rate: -32
rate: -111
rate: -12
rate: -25
rate: -4
rate: -55
rate: -47
rate: -30
rate: -16
rate: -23
rate: -31
rate: -49
rate: -14
rate: -25
rate: -16
rate: -10

这是缓缓移动传感器,有这些数据怎么能得到角度?

怎么用C语言通过角速度求出角度?求个函数~~~rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: 0rate: -1rate: 1rate: 0rate: 0rate: 7rate: 4rate: 0rate: 4rate: 4rate: 0rate: 0rate: 1rate: 0rate: 0rate: 0rate: 3rate: 1rate: 1rate: 0r
积分,角度就是rate-t坐标所围面积,但看你得到的rate是离散的,也就只能用近似求解了,将每个rate乘以采样周期(也就是相邻两个rate值的时间间隔),如果是单速率采样,就可以简化为将所有rate相加,和*T=angle,精度还是很高的.不知这个解答可以吗?

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