5x+cosx=0show that the equation 5x+cosx=0 has a solution.Are there many solution?

5x+cosx=0show that the equation 5x+cosx=0 has a solution.Are there many solution? the function f is defined by f(X)=cosec x + tan2x ,A.show that the roots of f(x)=0 satisfy the pls solve the function f is defined by f(X)=cosec x + tan2x ,A.show that the roots of f(x)=0 satisfy the equation2cos^3 (x) -2cos^2(X)-2cosx+1=0 Wasn't that a great talent show? 设t=cosx,x=?用t表示. cosx=t,用字母t表示X Find all possible functions with the derivative f'(x)= cosx - 2(e^2x)+5Need to show how you work it out. Thanks! sinX-cosX=t^5 求sinX+cosX=? 英语翻译show that a free-falling ball dropped vertically from the rest travels three times as far from t = 1s to t = 2s as from t =0 to t = 1s想让我SHOW什么出来,这么说SHOW都是证明的意思么? ∫(0,x)(x-t)f(t)dt=1-cosx,证明∫(0,π/2)dx=1 f【x】=e∧2x+（1-2t）e∧x+t²,求证当x≥0时,f【x】+cosx≥x+2当x≥0时,f【x】+cosx≥x+2 given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0 求函数f(x)=2cosx+3sin2x-2sinx+5的最大值和最小值,并求出取最小值时x的值令cosx-sinx=t,则t∈[-√2,√2].cosx-sinx=t的两边同时平方,得到1-sin2x=t^2,所以sin2x=1-t^2.所以f(x)=2cosx+3sin2x-2sinx+5=2t+3(1-t^2)+5=f(t)=-3t^2 假设t=sinx+cosx x属于[0,π/2] 换元后的t的取值范围如何求呢? 一道数学题：已知函数f(t)=√[(1-t)/(1+t)],g(x)=cosx*f(sinx)+sinx*f(cosx),x属于（π,17π/12）已知函数f(t)=√[(1-t)/(1+t)],g(x)=cosx*f(sinx)+sinx*f(cosx),x属于（π,17π/12）.（1）将函数g(x)化简成Asin（ωx+φ）+B（A＞0 英语翻译studies show that deeds don’t match word 函数y=2/cosx+cosx/2(0≤x lim(x→0)〖(∫[cosx,0](e^t-t)dt/x^4 〗 reality tv show 用英文来翻译 比如:documentary=A T.V show that talks about real life events.这样