一道英文数学题,是有关排序组合的Exactly 4 actors try out for 4 parts in a play.If each actor can perform any one part and no one will perform more than one part,how many different assignments of actors are possibe?

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一道英文数学题,是有关排序组合的Exactly 4 actors try out for 4 parts in a play.If each actor can perform any one part and no one will perform more than one part,how many different assignments of actors are possibe?
一道英文数学题,是有关排序组合的
Exactly 4 actors try out for 4 parts in a play.If each actor can perform any one part and no one will perform more than one part,how many different assignments of actors are possibe?

一道英文数学题,是有关排序组合的Exactly 4 actors try out for 4 parts in a play.If each actor can perform any one part and no one will perform more than one part,how many different assignments of actors are possibe?
四对四的排列.
4*3*2*1=24.
即可能有二十四中排列方法.
你用排列数算也是这个结果的..这里不好打上下标..所以我就写了个式子...

4个演员演四出戏，如果每个演员都可以胜任每出戏，而每个演员只能演一出戏，有多少种排列方案？
4*3*2*1=24种

This is an obvious permutation problem.
在一场话剧裏有四位演员分演四个部分，每位演员能且只能演出其中一部分，问有多种组合方法？
SOL: 4!=4 X 3 X 2 X 1= 24
Ans: There are 24 different assignments of actors possible.

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