设{an}是公差大于0的等差数列,若a1+a2+a3=80,则a11+a12+a13=?

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设{an}是公差大于0的等差数列,若a1+a2+a3=80,则a11+a12+a13=?
设{an}是公差大于0的等差数列,若a1+a2+a3=80,则a11+a12+a13=?

设{an}是公差大于0的等差数列,若a1+a2+a3=80,则a11+a12+a13=?
设首项为a,公差为d,则:
a1+a2+a3=80
===> a1+(a1+d)+(a1+2d)=80
===> 3a1+3d=80
===> 3(a1+d)=80
a11+a12+a13=(a1+10d)+(a1+11d)+(a1+12d)
=3a1+33d
——缺少条件,无法计算!

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