作业帮5c/6a^2b+7a/8b^2c-b/12a^2c通分计算
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5c/6a^2b+7a/8b^2c-b/12a^2c通分计算
5c/6a^2b+7a/8b^2c-b/12a^2c通分计算
5c/6a^2b+7a/8b^2c-b/12a^2c通分计算
5c/6a^2b+7a/8b^2c-b/12a^2c
=(5/6)c*a^(-2b)+(7/8)a*b^(-2c)-(1/12)b*a^(-2c)
=a^(-2b)*{[(5/6)c]+[(7/8)a^(2b+1)*b^(-2c)]-[(1/12)b*a^(2b-2c)]}
=[a^(-2b)*b^(-2c)]*{[(5/6)c*b^(2c)]+[(7/8)a^(2b+1)]-[(1/12)b^(2c)*a^(2b-2c)]}
=[a^(-2b)*b^(-2c)*a^(-2c)]*{[(5/6)c*b^(2c)*a^(2c)]+[(7/8)a^(2b+2c+1)]-[(1/12)b^(2c)*a^(2b)]}
=[(5/6)(ab)^(2c)*c+(7/8)a^(2b+2c+1)-(1/12)a^(2b)*b^(2c)]/[a^(2b+2c)*b^(2c)]
=[20(ab)^(2c)*c+21a^(2b+2c+1)-2a^(2b)*b^(2c)]/[24a^(2b+2c)*b^(2c)]
5c/6a^2b+7a/8b^2c-b/12a^2c
=(5c*4bc+7a*3a^2-b*2b^2)/24a^2b^2c
=(20bc^2+21a^3-2b^3)/24a^2b^2c
初二分式的加减法2a-b-c/（a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c-a)3a-6b/a+b- 5a-6b/a-b- 4a-5b/a+b+ 7a-8b/b-a注：有空格的地方是下一个分式
化简：7(a-b-c)-5(a+b-c)+3(a-b-c)+(a+b-2)
2a(a+b-c)-3b(a+b-c)+5c(c-a-b)
5a+{3b+[6c-2a-2(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c）]
5a-｛-3b+[6c-2a-(a-c)}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
计算：5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5c/6a^2b+7a/8b^2c-b/12a^2c
5c/6a^2b+7a/8b^2c-b/12a^2c通分计算
[b/(a-b+c)]+[(2a+c)/(b-a-c)]-[(b-c)/(b-a-c)]
b/a-b+c+2a+c/b-a-c-b-c/b-c-a
a-c+b=5 a+b+c=7 a-b-c=2 求a b c
a+6b等于c,2a-2b等于5c,求a:b;c
(a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b)
已知5a=8b,7c=2b,求a:b:c
已知a+b/2=b-2c/3=3c-a/4,则5a+6b-7c/8a+9b=_________
已知(a+b)/2=(b-2c)/3=(3c-a)/4,求(5a+6b-7c)/(8a+9b)的值.