x2+2xy-8y2+2xy+14yz-3z2二次三次项的因式分解

x2+2xy-8y2+2xy+14yz-3z2二次三次项的因式分解 x2+y2+z2-2xy+2yz+2zx=? 因式分解 a3b-ab3+a2+b2+1 3x2-11xy+6y2-xz-4yz-2z2 x2-8xy+15y2+2x-4y-3 计算：(xy-x2)÷xy分之x2-2xy+y2 (x2+2xy+y2)( x2-xy+y2)2 化简 (x2-2xy+y2)-(x2+2xy+y2)=什么 ( x2+xy+y2) ( x2+xy+2y2)-12y4 x2-2xy-8y2因式分解 x2-2xy+y2-9 已知,x/2=y/3=z/4,求xy+yz+zx/x2+y2+z2????? 6x2-7xy-3y2-xz+7yz-2z2分解因式 为什么（y3/z+z3/x+x3/y）(yz+zx+xy)>=(y2+x2+z2)2 因式分解：3x2-11xy+6y2-xz-4yz-2z2 (8xy- x2+y2)-(x2-y2+8xy) 2是平方 已知：x/2=y/3=z/4,求（x2+y2-z2-2xy）/（x2-y2+z2-2xz）除以（x2-y2-z2+2yz)/(x2+y2-z2+2xy) 已知：x/2=y/3=z/4,求（x2+y2-z2-2xy）/（x2-y2+z2-2xz）除以（x2-y2-z2+2yz)/(x2+y2-z2+2xy) 因式分解x2-y2-z2-2yz+1-2x x2-6xy-10x+30 y+25 求证:(x2-xy+y2)3+(x2+xy+y2)3能被2x2+2y2整除