已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)

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已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)
已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)

已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)
我想您的题目是│ab-2│+│b-2│=0吧?
∵│ab-2│≥0,│b-2│≥0
∴ab=2,b=2
∴a=1,b=2
∴原式=1/(1×2)+1/(2×3)+..+1/(2007×2008)
=1-1/2+1/2-1/3+..+1/2007-1/2008
=1-1/2008
=2007/2008
明教为您解答,
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