15/51-15‖2∠5∪5∩4∈5⊙6∑7

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 21:05:07

15/51-15‖2∠5∪5∩4∈5⊙6∑7
15/51-15‖2∠5∪5∩4∈5⊙6∑7

15/51-15‖2∠5∪5∩4∈5⊙6∑7
8.525464787106120127237198091290817915329743194070729732429127415978072394051254579387928319834719569859084716598624982398471926531515912365904012502135610521358610295621395623984129835712938651293859127349081659126359812374871239847192865129835912835791823740165981326189273409831265098237498237509821375092187350928375098275021365987320952913865098237509238746598236094872130984709165982136598739852734961293845981237409812365981230948710923847.

15/51-15‖2∠5∪5∩4∈5⊙6∑7 简便方法急⊙﹏⊙b汗 8分之5×(5÷(6分之5-4分之3) 3分之7-(8分之5-8分之5÷16分之15) 交集并集设U={x∈N|0《x《或=于10},A={1,2,4,5,9},B={4,6,7,8,10},C={3,5,7},求A∩B,A∪B,(CuA)∩(CuB),(CuA)∪(CuB),(A∩B)∩C,(A∪B)∪C.帮哈忙 已知A={1,2,3,4},B={3,4,5,6},C={1,3,4,6},求 A∩BA∩CA∪BA∪CB∩CA∩空集B∪CC∪空集 35(X-2)+15(5X-6)=(22X-51)+21(3X-4) .5.定义A-B={x|x∈A且x B},5.定义A-B={x|x∈A且x B},若M={1,2,3,4,5},N={2,3,6},则M-(M-N)=( )A.M∩N B.N∪N C.{1,4,5} D.{6} 为什莫? (1/15-1/51)×17×5的简便算法 已知全集∪={1,2,3,4,5,6,7},A={2,4,5},B={1,3,5,7},求A∩([∪B),([UA)∩([∪B) 15/2×5/9+4/7+11/5×6/5 5-5/4×2/15-5/6简便运算 5(2×-2)-6=6×-15 3分之2u十4分之3U =2分之1 5分之4u十6分之5∪=15分之7 1/3-2/15+3/35-4/63+5/99-6/143= 要简便算法, 已知A={1,2,3,4,5},若a∈A,则6-a∈A的非空集合A的个数为几个?并写出这些集合如题 还有这题 A={x|-2﹤x-1≤3},B={-4<x<-1}若集合C同时满足下列两个条件①C∈(A∪B)∩Z;②当a∈C时,也有-a∈C,试写出 求比值:15:1/15;0.2kg:120g.化简:4/5:5/6=;117:78:51=. 已知A=﹛0,2,4,6,8﹜,B=﹛0,1,2,3,4,5﹜,C=﹛4,5,6﹜求(1)A∩B∩C (2)A∪B∪C (3)(A∩B)∪C (4)(A∪B)∩C 1+5×2÷6-7-8×86-42-5-15+6×52×7×5÷55-2= 设全集u={1,2,3,4,5,6},M={2,3,4,5},N={1,3,6},求[Cu(M∪N)∩(M∩N)设全集U={1,2,3,4,5,6},M={2,3,4,5},N={1,3,6},求[Cu(M∪N)]∩(M∩N)