已知x2-5x-2000=0,求(x-2)³-(x-1)²+1/x-2的值

已知x2-5x-2000=0,求(x-2)³-(x-1)²+1/x-2的值
已知x2-5x-2000=0,求(x-2)³-(x-1)²+1/x-2的值

已知x2-5x-2000=0,求(x-2)³-(x-1)²+1/x-2的值
设x-2=t 则(t+2)^2-5*(t+2)-2000=0
则 t^2-t=2006
原式：t^3-(t+1)^2+1/t
=t^3-t^2-2t/t
=t(t^2-t)-2t/t
=2004t/t
=2004