若x^2+y^2+2x-8y+17=0试求(x-3y)^2-(x+3y)^2的值
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若x^2+y^2+2x-8y+17=0试求(x-3y)^2-(x+3y)^2的值
若x^2+y^2+2x-8y+17=0试求(x-3y)^2-(x+3y)^2的值
若x^2+y^2+2x-8y+17=0试求(x-3y)^2-(x+3y)^2的值
x^2+y^2+2x-8y+1+16=0
(x^2+2x+1)+(y^2-8y+16)=0
(x+1)^2+(y-4)^2=0
平方大于等于0,相加等于0
若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
x+1=0
x=-1
y-4=0
y=4
(x-3y)^2-(x+3y)^2
=[x-3y+x+3y](x-3y-x-3y)
=2x×(-6y)
=-12xy=48
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
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