因式分解x2+2+y2-3x-2xy+3y

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因式分解x2+2+y2-3x-2xy+3y
因式分解x2+2+y2-3x-2xy+3y

因式分解x2+2+y2-3x-2xy+3y
x2+2+y2-3x-2xy+3y
=x2-2xy+y2-3x+3y+2
=(x-y)²-3(x-y)+2
=(x-y-2)(x-y-1)
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(x-y-1)(x-y-2)

x2+2+y2-3x-2xy+3y=(x-y)²-3(x-y)+2
=(x-y-1)(x-y-2)

原式=(x-y)²-3x+3y+2
=(x-y)²-3(x-y)+2
=(x-y-2)(x-y-1)

x-y-2)(x-y-1)