19-200x+100x*x=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 06:03:29

19-200x+100x*x=0
19-200x+100x*x=0

19-200x+100x*x=0
Δ=b²﹣4ac=(-200)²-4×19×100=32400
x=[-b±√﹙b²-4ac﹚]÷2a x₁=﹙200+180﹚÷2×100=1.9 x₂=﹙200-180)÷2×100=0.1

(10x-1)(10x-19)=0
x1=1/10 x2=19/10