有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 16:49:16

有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?

有两个底面积相等的圆柱,一个圆柱高6DM,体积是48DM³,另一个圆柱高为5DM,体积是多少?
48÷6×5=40dm³

48除以6=8 5*8=40

6*S=48 S=8 v=s*h=8*5=40

用公式带入计算：
s=v÷h
=48÷6
=8（dm³）
v=sh
=8×5
=40（dm³）

40DM³，圆柱体的体积等于底面积乘以高

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收起

圆柱的体积=底面积×高→底面积=体积÷高
这两个圆柱的底面积就是：48÷6=8（d㎡）
8×5=40（DM³）

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