化简log(1/a)b+log(a)b

化简log(1/a)b+log(a)b 1≤a≤b≤c,证明log(a)(b)+log(b)(c)+log(c)(a)≤log(b)(a)+log(c)(b)+log(a)(c) 求证 log(a)^(b)=1/log(b)^(a)求证 log(a)^(b)=1/log(b)^(a) 已知01比较log(a)(1/b),log(a)(b),log(b)(1/b)的大小 已知01.比较log a 1/b,log a b,log b 1/b的大小. 若a²>b>a>1,试比较log b b/a ,log b a,log a b的大小 设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a= 已知a＜b＜1,log(a)b+log(b)a=10/3,求log(a)b-log(b)a的值括号为下标, 已知01,则下列不等式中成立的是（ ）A.log(b)(1/b)＜log(a)(b)＜log(a)(1/b)B.log(a)(b)＜log(b)(1/b)＜log(a)(1/b)C.log(a)(b)＜log(a)(1/b)＜log(b)(1/b)D.log(b)(1/b)＜log(a)(1/b)＜log(a)(b) LOG （1／a ）b+LOGa b 化简 证明：log(A)M=log(b)M/log(b)A (b>0且b≠1）. log(a) (b ) 与log(b) (a)是什么关系 公式：log(a)(b)*log(b)(a)=? 2^(log(a)(b))*8^(log(a)(b)) 对数转换log (1/b)(a)可化为 -log b(a)log (1/a)(b)可化为 -log a(b)看不懂怎么转换的, log(a)(b)=log(c)(b) /log(c)(a) 怎么证log(a)(b)=log(c)(b) /log(c)(a)怎么证 27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log Log(2)1/25•log(3)1/8•log(5)1/9化简 还有已知log(18)9=a,log(18)5=b求log(36)45 值